Kinetic Energy Question (1 Viewer)

[mtsmahia]

Hi,

Can anyone please help me solve this question

A watermelon of 10.0kg, initially at rest, is moved by a force of 20N --> over a frictionless distance of 10 m. the kinetic energy of the watermelon will be?

and

A squash ball m=25g, initially at rest, is hit by a squash racket with a force of 20N--> and is in contact for 0.025s. The final velocity of the ball is?

thanks!

 

[lolokay]

work = change in energy = force*distance
energy gain of watermelon is 20*10J = 200J

F= ma = mv/t
v = Ft/m
= 20*0.025/0.025 m/s
= 20m/s