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Late 90s problem (1 Viewer)
- Thread starter harrisony
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SpiralFlex
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i) nth square has an area of
^2)
(n+1)th square has an area of
+4)^2=(2n+6)^2)
Clearly, the nth stripe is made out of the (n+1) th square - the nth square.
Hence
^2-(2n+4)^2=(8n+20) \; $cm$^2)
ii) The area of 1st stripe is,
+20)=28 \; $cm$^2)
The area of last stripe is,
+20))
iii) Now the total cost for the gold paint is, give by the total area summed up by the stripes.
)
Hence the gold paint cost is
(n+1)th square has an area of
Clearly, the nth stripe is made out of the (n+1) th square - the nth square.
Hence
ii) The area of 1st stripe is,
The area of last stripe is,
iii) Now the total cost for the gold paint is, give by the total area summed up by the stripes.
Hence the gold paint cost is
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Timske
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wooowi) nth square has an area of
(n+1)th square has an area of
Clearly, the nth stripe is made out of the (n+1) th square - the nth square.
Hence
ii) The area of 1st stripe is,
The area of last stripe is,
iii) Now the total cost for the gold paint is, give by the total area summed up by the stripes.
Hence the gold paint cost is
SpiralFlex
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Huh?
zeebobDD
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he is surprised at your intelligence
nightweaver066
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In awe*
SpiralFlex
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What? Anyone could have done that question, I was initially not bothered but procrastination got in...
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