C cattle_7 cattle Joined Mar 28, 2005 Messages 5 Location NSW, Australia Gender Female HSC 2006 Mar 14, 2009 #1 I am having trouble with finding the limit, as x approaches 0 of (1-cosx)/xsinx. can anyone help?
T Timothy.Siu Prophet 9 Joined Aug 6, 2008 Messages 3,449 Location Sydney Gender Male HSC 2009 Mar 14, 2009 #2 cattle_7 said: I am having trouble with finding the limit, as x approaches 0 of (1-cosx)/xsinx. can anyone help? Click to expand... (1-cosx)/xsinx =limx-->0 2sin2(x/2)/xsin x =limx-->0 sin(x/2)/(x/2) . sin(x/2)/2sin(x/2)cos(x/2) =limx-->0 1 x 1/[2cos(x/2)]=1/2
cattle_7 said: I am having trouble with finding the limit, as x approaches 0 of (1-cosx)/xsinx. can anyone help? Click to expand... (1-cosx)/xsinx =limx-->0 2sin2(x/2)/xsin x =limx-->0 sin(x/2)/(x/2) . sin(x/2)/2sin(x/2)cos(x/2) =limx-->0 1 x 1/[2cos(x/2)]=1/2
C cattle_7 cattle Joined Mar 28, 2005 Messages 5 Location NSW, Australia Gender Female HSC 2006 Mar 14, 2009 #3 thanks