I izzy_xo Member Joined Apr 19, 2009 Messages 59 Gender Female HSC 2010 Jun 1, 2010 #1 hey just wondering if anyone could help me with this question: Find the eqn of the circle that passes through (7,2) (2,-3) and (-4,-1) many thanks.
hey just wondering if anyone could help me with this question: Find the eqn of the circle that passes through (7,2) (2,-3) and (-4,-1) many thanks.
H hscishard Active Member Joined Aug 4, 2009 Messages 2,033 Location study room...maybe Gender Male HSC 2011 Jun 1, 2010 #2 A really bad way of doing it is substitue the points into (x-h)^2+(y-k)^2 = r^2 And then simultaneously solve
A really bad way of doing it is substitue the points into (x-h)^2+(y-k)^2 = r^2 And then simultaneously solve
Affinity Active Member Joined Jun 9, 2003 Messages 2,062 Location Oslo Gender Undisclosed HSC 2003 Jun 1, 2010 #3 hscishard said: A really bad way of doing it is substitue the points into (x-h)^2+(y-k)^2 = r^2 And then simultaneously solve Click to expand... That's probably the best way without resorting to heavy machinery. alternatively you can find the equation of 2 perpendicular bisectors of the line segments joining 2 points and solving them to get the center.
hscishard said: A really bad way of doing it is substitue the points into (x-h)^2+(y-k)^2 = r^2 And then simultaneously solve Click to expand... That's probably the best way without resorting to heavy machinery. alternatively you can find the equation of 2 perpendicular bisectors of the line segments joining 2 points and solving them to get the center.
H hscishard Active Member Joined Aug 4, 2009 Messages 2,033 Location study room...maybe Gender Male HSC 2011 Jun 1, 2010 #4 Ooo nice. Note that that method uses 3unit maths.