Logarithm problems =[ (1 Viewer)

Finx · Mar 3, 2009

If logb2 = 0.6 and logb3 = 1.2, find:

a) logb6b
b) logb8
c) logb1.5b²

The "b" in "logb" is subscript. Most of the logarithm stuff we've done in class has gone way over my head, I'm really lost.

Thanks in advance!

hermand · Mar 3, 2009

lol. did these exact questions the other day.
a.
$\log _{b}(3\times 2\times b)=\log _{b}3+\log _{b}2+\log _{b}b$
by substitution,
$=0.6+1.2+1=2.8$
since $\log _{b}b=1$ , as a log function with the same base as 'big number' [can't remember the name for it] =1.

b.
$\log _{b}8=\log _{b}(2\times2\times2)$
$3\log _{b}2=3(0.6)=1.8$
using the same log rule as before.

c.
$\log _{b}(1.5b^{2})=\log _{b}\left (\frac{3}{2} \right )+\log _{b}(b\times b)$
$=\log _{b}3-\log _{b}2+\log _{b}b+\log _{b}b$
$=1.2-0.6+1+1=2.6$

is you need help with any of that or you'd like me to explain the log rules, let me know =]].

Finx · Mar 3, 2009

Marry me?

Thanks so much =D

Edit; more questions possibly coming soon ._.

hermand · Mar 3, 2009

haha anytime =]]. just send them my way =pp.

Logarithm problems =[ (1 Viewer)

Finx

Member

hermand

je t'aime.

Finx

Member

hermand

je t'aime.

Users Who Are Viewing This Thread (Users: 0, Guests: 1)