O OToole New Member Joined Nov 14, 2005 Messages 18 Gender Male HSC 2006 Feb 18, 2006 #1 1.3 Grams of Zinc react with excess hydrochloric acid at SLC (in which one mole of gas 24.5 L). What volume of Hydrogen gas forms? The answer is 0.487L but I keep getting half that.
1.3 Grams of Zinc react with excess hydrochloric acid at SLC (in which one mole of gas 24.5 L). What volume of Hydrogen gas forms? The answer is 0.487L but I keep getting half that.
P pLuvia Guest Feb 18, 2006 #2 Nope I got 0.487L did you get the equation right? 2Zn(s) + 4HCl(aq) ---> 2ZnCl2(aq) + 2H2(g) Since the charge of Zn2+ and Cl-
Nope I got 0.487L did you get the equation right? 2Zn(s) + 4HCl(aq) ---> 2ZnCl2(aq) + 2H2(g) Since the charge of Zn2+ and Cl-
+:: $i[Q]u3 ::+ Jaded Member Joined Apr 28, 2003 Messages 898 Gender Female HSC 2003 Feb 18, 2006 #3 pLuvia said: Nope I got 0.487L did you get the equation right? 2Zn(s) + 4HCl(aq) ---> 2ZnCl2(aq) + 2H2(g) Since the charge of Zn2+ and Cl- Click to expand... With a balanced equation the numbers should be in lowest common multiples. The answer is correct though, the working's attached. Handy dandy cybershot =)
pLuvia said: Nope I got 0.487L did you get the equation right? 2Zn(s) + 4HCl(aq) ---> 2ZnCl2(aq) + 2H2(g) Since the charge of Zn2+ and Cl- Click to expand... With a balanced equation the numbers should be in lowest common multiples. The answer is correct though, the working's attached. Handy dandy cybershot =)