Hey peeps, could someone pretty please help me with this one question on Rates of Change?
A square pyramid has height twice its side length s. I proved that V=(2/3)s^3 and that A = (squareroot17 + 1)s^2. Hence find the rate at which V and A are decreasing when the side length is 4 metres if the side length is shrinking at 3mm/s.
I got my formula as dV/dt = ds/dt (times) dV/ds but I never get the answer right - i think it might have something to do with the metres/mm thing. The answer is 0.096m^3/s and (3/125)(root17 +1)m^2/s.
A square pyramid has height twice its side length s. I proved that V=(2/3)s^3 and that A = (squareroot17 + 1)s^2. Hence find the rate at which V and A are decreasing when the side length is 4 metres if the side length is shrinking at 3mm/s.
I got my formula as dV/dt = ds/dt (times) dV/ds but I never get the answer right - i think it might have something to do with the metres/mm thing. The answer is 0.096m^3/s and (3/125)(root17 +1)m^2/s.
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