• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page

Maxima Problem (1 Viewer)

Carly_57

New Member
Joined
Nov 13, 2005
Messages
3
Location
Menangle Park
Gender
Female
HSC
2006
A piece of wire of length 120cm is bent to form a rectangle. Find the dimesions of the rectangle is the area is to be a maximum.

I have no idea where to go with this one. Thanks
 

Riviet

.
Joined
Oct 11, 2005
Messages
5,593
Gender
Undisclosed
HSC
N/A
Let the width and breadth of rectangle be a and b.
2a+2b=120
a+b=60
b=60-a *
Area=ab
=a(60-a)
=60a-a2
d/dx(60a-a2)=60-2a=0
2a=60
a=30
.'. b=60-30
=30
.'. dimensions of rectangle that make area a max are 30cm by 30cm.
 
P

pLuvia

Guest
You should know that for maximum area of a rectangle the sides are equal. So the maximum area would be a square
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top