mod6 (1 Viewer)

[kkk579]

for a uniform electric field (between 2 parallel plates), is net work always 0 for non conservative systems? for example, let's say that a positive charge experiences a force to the right by the e field and applies a physical force to the left, which causes the charge to move left of a distance 'd'. since the charge exists in a uniform field work (external) = qed, where work (e field) = -qed. this is what was said in a recording however this can only be true if the magnitude displacement of the particle caused by each force is equal right? so net work wouldnt always = 0

 

[kkk579]

bump

 

[wizzkids]

I think you are confusing a uniform electric field strength with equipotential. You should try to draw a diagram to explain your thoughts.

If a space contains a uniform electric field (as in your case of the parallel charged plates) then there is a uniform potential gradient from one plate to the other. Any charged particle will experience a force in this space and will move accordingly ( unless it is restrained by another equal and opposite force). If a positive charge is stationary relative to the field, then work W = qEd = 0 because d= 0. If a positive charge moves in the direction of the E-field then work is done by the field on the particle W= qEd. If a positive charge moves against the E-field then external work has been done where W = -qEd
Does that make sense?
(by the way, little-e is used in Physics for the charge on the electron, and capital-E is used for the electric field)