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pLuvia

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Area of a segment
1/2r2(θ-sinθ), θ is in radians
a)
A=1/2(3)2(pi/3-sin{pi/3})
A=0.8153m2
b)
A=1/2(10)2(5pi/6-sin{5pi/6})
A=166.435m2
 

Mc_Meaney

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Can someone help me make sense out of this question:

"Given the wingspan of an aeroplane is 30m, find the plane's altitude to the nearest metre if the wingspan subtends an angle of 14' when directly overhead
 

SoulSearcher

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Its asking you to find the straight line distance from the observer to the plan. Since the edges of the wings make an angle of 14' with the observer, draw a triangle joining the edges of the wing to the observer. then solve from there by drawing a perpendicular line to the wing from the observer, then use trig ratios.
 

SoulSearcher

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Ok then, f(x) = e2x(1-x)
f'(x) = 2e2x(1-x) - e2x
= e2x(1-2x)
f'(x) = 0 to find stationary points
0 = e2x(1-2x), but as e2x cannot equal 0, then
1-2x = 0
2x = 1
x = 1/2
therefore f(1/2) = e2*0.5 * (1-0.5)
= 0.5e,
therefore coordinate of stationary point is (0.5, 0.5e)
 
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KnightSaber

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Mc_Meaney said:
Can someone help me make sense out of this question:

"Given the wingspan of an aeroplane is 30m, find the plane's altitude to the nearest metre if the wingspan subtends an angle of 14' when directly overhead
tan14 = x/30

x= 7.4798m '''



Lol i hope the plane isnt acutally flying...

when u say over head do u mean the person is standing underneath the plane?

Please use angles of D & A
 

Riviet

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The distance between the tips of the wings, as of a bird or insect, when fully extended.
Ah yes, understanding exactly what the question is asking is always important. ;)
 

insert-username

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I assume this is cos x all to the power of -1. You use the chain rule:

dy/dx = dy/du . du/dx where u = cos x

dy/dx = -(cosx)-2.(-sinx)

= sinx/cos2x

= tan x sec x


I_F
 

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