need help with integration question (1 Viewer)

[kangarulz]

Find the total area of the region bounded by f(x)=x^3-x and g(x)=1-x^2

 

[pLuvia]

First you find the intersections where the graphs cross each other then observe the higher graph between the intersections then using integration find the area enclosed. Only find the area that is enclosed between the intersections

f(x)=x³-x
g(x)=1-x²

Simulanteously solving
x=-1,1

From drawing both the graphs you can see between x=1 and x=-1 g(x) is higher than f(x) . Taking into account the negative area you should be able to find the area

 

[kangarulz]

that's what im struggling with, finding the points of intersection and the a and b values

 

[pLuvia]

I editted my post if that helped or not?

But here's the full working for the simutaneous solving

x³-x=1-x²
x³+x²-x-1=0
x²(x+1)-(x+1)=0
(x²-1)(x+1)=0
x=+1,-1

 

[Riviet]

Most of the time, drawing a diagram does help.