B Bongo New Member Joined Oct 16, 2018 Messages 4 Gender Male HSC 2019 Feb 12, 2019 #1 Find the equation of the tangent to the curve y= 4^x +1 at the point (0,4). The answer from the textbook is 4 ln 4 * x- y+ 4=0 . I'm not sure how to get that answer. Any help will be greatly appreciated.
Find the equation of the tangent to the curve y= 4^x +1 at the point (0,4). The answer from the textbook is 4 ln 4 * x- y+ 4=0 . I'm not sure how to get that answer. Any help will be greatly appreciated.
I InteGrand Well-Known Member Joined Dec 11, 2014 Messages 6,078 Gender Male HSC N/A Feb 12, 2019 #2 Bongo said: Find the equation of the tangent to the curve y= 4^x +1 at the point (0,4). The answer from the textbook is 4 ln 4 * x- y+ 4=0 . I'm not sure how to get that answer. Any help will be greatly appreciated. Click to expand...
Bongo said: Find the equation of the tangent to the curve y= 4^x +1 at the point (0,4). The answer from the textbook is 4 ln 4 * x- y+ 4=0 . I'm not sure how to get that answer. Any help will be greatly appreciated. Click to expand...
I InteGrand Well-Known Member Joined Dec 11, 2014 Messages 6,078 Gender Male HSC N/A Feb 12, 2019 #3 Bongo said: Find the equation of the tangent to the curve y= 4^x +1 at the point (0,4). The answer from the textbook is 4 ln 4 * x- y+ 4=0 . I'm not sure how to get that answer. Any help will be greatly appreciated. Click to expand...
Bongo said: Find the equation of the tangent to the curve y= 4^x +1 at the point (0,4). The answer from the textbook is 4 ln 4 * x- y+ 4=0 . I'm not sure how to get that answer. Any help will be greatly appreciated. Click to expand...
