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Partial Fractions Q10 (2 Viewers)

KFunk

Psychic refugee
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HSC
2005
x = a(x<sup>2</sup> +9) + (bx +c)(x+1)
= (a+b)x<sup>2</sup> + (b+c)x + 9a + c

a+b=0
b+c=1
9a+c=0

solve simultaneously and a= -1/10, b= 1/10, c=9/10 so you get:
1/10 &int; x/(x<sup>2</sup> +9) + 9/(x<sup>2</sup> +9) - 1/(x+1) dx

= 1/10[(1/2)ln(x<sup>2</sup> +9) + 3tan<sup>-1</sup>(x/3) -ln(x+1)] + C
 

3.1415926535897

Pi Pi Pi Pi Pi Pi Pi Pi!!
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have u learnet partial fractions yet...

cos that is like the first q's u do...
 

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