need help on 4. Answer is: D but i got C.
shaon0 ... Joined Mar 26, 2008 Messages 2,029 Location Guess Gender Male HSC 2009 Sep 10, 2008 #1 need help on 4. Answer is: D but i got C.
3unitz Member Joined Nov 18, 2006 Messages 161 Gender Undisclosed HSC N/A Sep 10, 2008 #2 intensity is inversly proportional to distance squared: I = k/d^2 intensity halved, distance tripled: I = [k/(3d)^2]/2 I = k/18d^2 i.e. 1/18th of the original Last edited: Sep 10, 2008
intensity is inversly proportional to distance squared: I = k/d^2 intensity halved, distance tripled: I = [k/(3d)^2]/2 I = k/18d^2 i.e. 1/18th of the original
shaon0 ... Joined Mar 26, 2008 Messages 2,029 Location Guess Gender Male HSC 2009 Sep 10, 2008 #3 3unitz said: intensity is inversly proportional to distance squared: I = k/d^2 intensity halved, distance tripled: I = [k/(3d)^2]/2 I = k/18d^2 i.e. 1/18th of the original Click to expand... Oh....my bad.I read the question wrong. My solution was: I=1/d^2 I/2 = 1/(3d)^2 I/2 = 1/9d^2 Thus, I=(2/9)(1/d^2)
3unitz said: intensity is inversly proportional to distance squared: I = k/d^2 intensity halved, distance tripled: I = [k/(3d)^2]/2 I = k/18d^2 i.e. 1/18th of the original Click to expand... Oh....my bad.I read the question wrong. My solution was: I=1/d^2 I/2 = 1/(3d)^2 I/2 = 1/9d^2 Thus, I=(2/9)(1/d^2)
