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thx but for the first one how'd you know it = (x^2+2x-4)(x^2+2x+5)=0 on the first step??
Soor
For the other one, the double root will be a root of the derivative, soand
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So
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answer that one please xDDIt's a bit boring though.
See if you can solveexactly.
(The 1969 3 unit paper asked for the approximate solution to this using Newton's method, but you can actually solve it exactly.)
I too would like to know!It's a bit boring though.
See if you can solveexactly.
(The 1969 3 unit paper asked for the approximate solution to this using Newton's method, but you can actually solve it exactly.)
have you tried getting a Girl friend to fill in your spare time?Somewhat uglier, but equivalent expressions from wolframalpha.com yield the four roots, the last two of which are the complex roots:
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