shmickmick
New Member
- Joined
- Aug 27, 2005
- Messages
- 18
- Gender
- Male
- HSC
- 2006
hey just wondering if anyone could help me with a question as im the only guy doing it in my skool..............
for P(x) 2x^3 - x^2 - 6x +3
how do you find that x= 1/2 for the trial and error method i thought it could only be a factor of 3 and 2 eg 2/3 ,3/2, 1 etc
thanks........mick
for P(x) 2x^3 - x^2 - 6x +3
how do you find that x= 1/2 for the trial and error method i thought it could only be a factor of 3 and 2 eg 2/3 ,3/2, 1 etc
thanks........mick