• YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page

polys (2 Viewers)

Timothy.Siu

Prophet 9
Joined
Aug 6, 2008
Messages
3,449
Location
Sydney
Gender
Male
HSC
2009
if the roots of the equation x^3+3x^2-2x+1=0 are a,b,c, find the value of

a)a^2(b+c)+b^2(a+c)+c^2(a+b)
 

Iruka

Member
Joined
Jan 25, 2006
Messages
544
Gender
Undisclosed
HSC
N/A
a^2(b+c)+b^2(a+c)+c^2(a+b) = ab(a+b+c) + ac(a+b+c) + bc(a+b+c) - 3abc
 

azureus88

Member
Joined
Jul 9, 2007
Messages
278
Gender
Male
HSC
2009
Iruka said:
a^2(b+c)+b^2(a+c)+c^2(a+b) = ab(a+b+c) + ac(a+b+c) + bc(a+b+c) - 3abc
how are you supposed to see that coming, or it just somethin you're meant to remember?
 

gurmies

Drover
Joined
Mar 20, 2008
Messages
1,209
Location
North Bondi
Gender
Male
HSC
2009
my god, that's a wild-ball of a question. I saw the word "polys", one of my favourite topics and thought, "time to solve some questions." The only way I can think of is to do what was suggested, to go sum of roots multiplied by sum of roots taken two at a time and account for any terms you have added on.
 

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,250
Gender
Male
HSC
2006
It's not that hard. Just expand, collect terms and factorise. You should discover the pattern when you group them.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 2)

Top