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prob question (1 Viewer)

didi

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from the 1988 hsc paper, Q9(b)ii:
"A die whose faces are numbered 1, 2, 3, 4, 5, 6 is tossed twice. The sum S of the numbers which appear uppermost on the die is calculated...
It is known that a 4 appears on the die at least once in the two throws. Find the probability that S is greater than 8"

The answer they gave was 4/11. I don't understand how they got this. please help!!

didi
 

mastermind

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Originally posted by didi
from the 1988 hsc paper, Q9(b)ii:
"A die whose faces are numbered 1, 2, 3, 4, 5, 6 is tossed twice. The sum S of the numbers which appear uppermost on the die is calculated...
It is known that a 4 appears on the die at least once in the two throws. Find the probability that S is greater than 8"

The answer they gave was 4/11. I don't understand how they got this. please help!!

didi
For there to be at least one 4, the sample space of the two numbers added S is:

1,4
2,4
3,4
4,4
5,4
6,4
4,1
4,2
4,3
4,4
4,5
4,6

which is 12 - but 4,4 is repeated so the sample space becomes 11

for the two numbers to be > 8, the possibilites are:

5,4
6,4
4,5
4,6

therefore, answer is 4/11
 
Last edited:

didi

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oh i see...
i bet if i get a q like that in the hsc i'll be sitting there for ages trying to work it out. aarrgh!! i'm so dumb!

thnx 4 that.

didi
 

Minai

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with those die probability questions, its easier to jus draw box diagrams (a grid which shows all the combinations)
it helps to understand the scope of the problem your given
 

mastermind

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Yeah MinAi, I agree. I did that for this question, but had to write out all the combinations cause i cant put a table in here (can I??)

So, that is a good suggestion, it really does help for this type of problem.
 

mastermind

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Originally posted by Lazarus
You can use HTML codes to insert tables.
Oh, ok. Thanks Lazarus.

Still, I would have typed out the same amount of info anyway. But it would have been more helpful to do it that way.
 

spice girl

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Man, how complicated can chucking two dice be?

You can probably do it in your head.

Remember, if chucking 2 dice, one number is known, then sample space is 11.
 

Minai

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sorry spice...but we here dont do 4U or have Ruse-capacity-knowledge (well, some of us anyway..)

:D
 

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