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Vampire

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Hey everyone, I'm having a little trouble with this question so any help would be appreciated...

A tennis match between two players consist of a number of sets. The match continues until one of the players has won 3 sets.
Whenever Pat and John play, on average, for each set they play, there is a probability of 2/3 that Pat wins and a probability of 1/3 that John wins.

Find Probability that Pat wins match (4 marks)

Thx
 

Ogden_Nash

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I'll give it a shot....(no pun intended :) )

P(Pat winning) = P(win in 3 sets) + P(win in 4 sets) + P(win in 5 sets)
........................= (2/3)<sup>3</sup> + (2/3)*<sup>3</sup>C<sub>1</sub>*(2/3)<sup>2</sup>*(1/3) + (2/3)*<sup>4</sup>C<sub>2</sub>*(2/3)<sup>2</sup>*(1/3)<sup>2</sup>
........................= 64/81

[Note: for a 4 or 5 setter, the final set must be won by Pat, so only the remaining sets may be ordered differently.]

Hope that helps.
Someone please correct me if I've made a mistake...
 
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shafqat

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It has to finish in 5 sets, as by then someone will have one 3 of them.
 

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