Problem! (1 Viewer)

[Kabeio]

Hw do you find the second derivative of the following:

10 sin pi(t)/2

Thanks,

 

[haboozin]

Hw do you find the second derivative of the following:

10 sin pi(t)/2

Thanks,

f' = 5pi cos pit/2
f'' = -5/2pi^2 sinpit/2
f''(t) = -pi/2^2f(x)

 

[Kabeio]

i dont get how you go from f'' to f''(t) ?

 

[rnitya_25]

because i don't think your (t) was meant to mean that you need to subtitute t in....the 2nd line is right i think

 

[speed2]

f(t) = 10 sin [П(t)/2]

f'(t) = 5П cos [П(t)/2]

f''(t) = -5/2.П^2.{(1/10).10sin[П(t)/2]

since f(t)=10 sin [П(t)/2]

f''(t) = -5/2.П^2.{(1/10).f(t)]

f''(t) = -П/4^2f(t)