CrashOveride
Active Member
G'day :uhhuh:
Question: A body is projected with speed U from a height h, above a horizontal plane, at an angle &thetha; to the horizontal. Show that the range R on the horizontal is given by:
gR<sup>2</sup>sec<sup>2</sup>θ - 2U<sup>2</sup>Rtanθ - 2hU<sup>2</sup> = 0.
Hokay, did this first part then the next part says: Further show that the maxium range R<sub>1</sub> is given by:
R<sub>1</sub> = (U/g) . sqrt[ U<sup>2</sup> + 2hg ]
So my approach was to solve the quadratic in R from above, keeping in mind that we are after a maximum answer. Except i wasn't too sure were to go from here, i have attached an image (easier to read than writing here i take it) where i think im close just anyone got any hints from here? Thanks !
Question: A body is projected with speed U from a height h, above a horizontal plane, at an angle &thetha; to the horizontal. Show that the range R on the horizontal is given by:
gR<sup>2</sup>sec<sup>2</sup>θ - 2U<sup>2</sup>Rtanθ - 2hU<sup>2</sup> = 0.
Hokay, did this first part then the next part says: Further show that the maxium range R<sub>1</sub> is given by:
R<sub>1</sub> = (U/g) . sqrt[ U<sup>2</sup> + 2hg ]
So my approach was to solve the quadratic in R from above, keeping in mind that we are after a maximum answer. Except i wasn't too sure were to go from here, i have attached an image (easier to read than writing here i take it) where i think im close just anyone got any hints from here? Thanks !
Last edited: