Q6 b) i) (1 Viewer)

Synergie

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Yes, finding the value of k, in the question relating to Radium decay
 

Joustah

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Subbing in what you know, and knowing the ratio:

Ae^(k x 0) = 2Ae^(k x 1600)
simplify: e^(1600k) = 0.5
solve for k
 

Cataclysm

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Q = Ae^-kt

Q = A/3

.:. A/3 = Ae^-kt

1/3 = e^-kt

loge(1/3) = loge(e)^-kt

loge(1/3) = -ktloge(e)

loge(1/3) = -kt

-[loge(1/3)]/k = t

Which was like... Eh, I forget...
 

mitchwong650

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Yeah, I think Cataclysm's got it going on,

ends up being: 2536 to the nearest year
 

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