Question Help (1 Viewer)

[Mr Wiggle]

This question from Cambridge pg 251

(Three medians of a triangle are concurrent)

ABC is a triangle. E and F are the midpts of CA and AB respectively. BE and CF intersect at G. AG produced cuts BC at D. H is the point on AGD produced,such that AG=GH. show that

(a) GBHC is parallelogram
(b) BD=DC

 

[Constip8edSkunk]

a) u can prove the triangles AFG and ADH are similar, therefor as corresponding angles are equal FG||BH, similarly, u can prove AGE and AHC are similar and EG||CH, as FGC and EGB are straight lines, the opposite sides of GBHC r ||, .'. is a ||gram

b) use the property of ||grams where diagonals bisect eachother... ie BC is bisected at D

 

[Mr Wiggle]

Thanks for the help Constip8edSkunk