• Best of luck to the class of 2025 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here

Question on Application of Calculus to the Physical World (1 Viewer)

theodore0307

Active Member
Joined
Oct 31, 2013
Messages
221
Gender
Male
HSC
2014
I need help with the following question, 6.3 qu.17.jpg

Please show working out

Thanks
 

rumbleroar

Survivor of the HSC
Joined
Nov 30, 2011
Messages
2,271
Gender
Female
HSC
2014
a. t = 0
b. find h', let it equal to 0 (prove it is max as well) for max dist
c. acceleration, iirc is h", so sub t=0 and tmax into h" for the acceleration at these times
 

braintic

Well-Known Member
Joined
Jan 20, 2011
Messages
2,109
Gender
Undisclosed
HSC
N/A
Alternatively:

(b) Realise that the max/min values of the sine function are +/- 1.
These values will give the most +ve and most -ve displacements of +/- 3.
sin2t = +/- 1 when 2t=pi/2, 3pi/2, 5pi/2, ...
ie. t = pi/4, 3pi/4, 5pi/4, ...

(c) If you differentiate twice you get -12sin2t, and remembering that h=3sin2t, you get acc=-4x
Since the displacement at these points is x= +/- 3, then the acceleration is -/+ 12
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top