quick qn (1 Viewer)

[ronaldinho]

x_/(3-x)

x square root 3-x

... how do i graph this... i got most of it.. but i keep getting the differentiatin wrong..

i get sttationery pt as 6?

 

[SoulSearcher]

y = xrt(x-3)
y' = rt(3-x) - x/2rt(3-x)
y' = 0
0 = rt(3-x) - x/2rt(3-x)
x/2rt(3-x) = rt(3-x)
x = 2(3-x)
x = 6 - 2x
3x = 6
x = 2

 

[muttiah]

how did u differentiate it


i got

rt(3-x) + x/2rt(3-x) = 0

vu'+uv'=y' ?

 

[pLuvia]

You forgot the minus when you differentiated sqrt{3-x}