quick qu (1 Viewer)

[sikeveo]

differentiate y = sin(x^3)

easy question yes, but ive returned all my maths books to school

 

[icycloud]

Chain rule... d/dx (Sin[x^3]) = 3x^2 Cos[x^3]

Working: (normally you'd do this in your head)

u = x^3
du = 3x^2 dx
y = Sin[x^3] = Sin
dy = Cos du
= Cos[x^3] * 3x^2 dx

Thus, dy/dx = Cos[x^3] * 3x^2

 

[sikeveo]

Cheers guys.

btw aaron you better get 100.

 

[icycloud]

Cheers guys.

btw aaron you better get 100.

Lol no chance, I can't even top the school.. But thanks for the encouragement anyway

 

[Rax]

Dont Worry Icy I have faith in you
All I wan't to know is do Riviet and Pluvia go to the same school....because they are crazy good
Well From Observation

 

[SoulSearcher]

Nope .

 

[Riviet]

Haha, we're not from the same school, although we do like to help others around the forums. =D

 

[pLuvia]

He goes to private I go to public