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Timothy.Siu

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by considering the geometrical significance of (2^x - 1)/x to the graph of y = 2^x,

find:

lim (N^x-1)/x
x-->0
 

trailblazer

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It wasn't too hard. Just have to use a bit of logic.

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Affinity

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the limit is log(N)
doesn't look like 2 unit
 

Affinity

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well, near 0, the numerator is roughly log(N)*x....
 

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