What's the difference between a metal reacting in dilute acid and a metal reacting in a concentrated acid in terms of a redox reaction?
I have this question sheet which asks for the redox reaction of copper with dil. HNO3 then with conc. HNO3
this is the difference between the reduction reactions in the answers:
dilute ---> NO3^(-) + 4H^(+) + 3e^(-) -------> NO + 2H2O
concentrated --> NO3^(-) + 2H^(+) + e^(-) -------> NO2 + H2O
What is the rule or aspect of acid reactions that accounts for this?
I have this question sheet which asks for the redox reaction of copper with dil. HNO3 then with conc. HNO3
this is the difference between the reduction reactions in the answers:
dilute ---> NO3^(-) + 4H^(+) + 3e^(-) -------> NO + 2H2O
concentrated --> NO3^(-) + 2H^(+) + e^(-) -------> NO2 + H2O
What is the rule or aspect of acid reactions that accounts for this?