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sc maths help (1 Viewer)

super.muppy

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wat do u study for in ur maths hc trials
cuz teacher didn't say much
This is for 5.3 maths (advanced)
 
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-tal-

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Know your constructions, (bisecting angles etc), probability, and those stats tables, basic algebra
 
T

Troy2287

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Don't forget the stuff on Imaginative numbers...Eg. Finding the square root of -3 ;)
 

tommykins

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xXmuffin0manXx said:
:uhoh:

lol..no comment..

(notice the :uhhuh: )

i was being sarcastic =.=
They should really build a program that detects sarcasm via teh intraweb.
 

fullonoob

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super.muppy said:
wat do u study for in ur maths hc trials
cuz teacher didn't say much
This is for 5.3 maths (advanced)
lol your mup...copy using this site
I already told you look through past sc papers and basic year 9-10 questions.
 

Continuum

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Troy2287 said:
Don't forget the stuff on Imaginative numbers...Eg. Finding the square root of -3
You're doing 2U Maths and talking about complex numbers. You must be cool.

/sarcasm

fullonoob said:
does the " i " stand for imaginative???
Yeah. More correctly, it stands for the square root of -1.
 

x.Exhaust.x

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Continuum said:
You're doing 2U Maths and talking about complex numbers. You must be cool.

/sarcasm
LOL.

For SC, I didn't do any study for Maths and scraped a high band. Same with computing, highly competent lmao. The only study I did was for Geography, where I failed the half yearly (35%, no study), and got a mark of 88 for Geography in the SC. TAKE THAT 35% lol.

Remember kiddos, don't stress about the SC, it's only year 10. The only thing I benefited from the SC was the experience of the BOS people patrolling and giving instructions, which will be helpful for the HSC.
 
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fullonoob

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super.muppy said:
wat do u study for in ur maths hc trials
cuz teacher didn't say much
This is for 5.3 maths (advanced)
Past sc papers and basic yr 9-10 questions.
 

tommykins

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Continuum said:
You're doing 2U Maths and talking about complex numbers. You must be cool.

/sarcasm



Yeah. More correctly, it stands for the square root of -1.
Yep, but we don't necessarily define "i" as the sqrt of -1, it's more so i² = -1.
 

Continuum

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tommykins said:
Yep, but we don't necessarily define "i" as the sqrt of -1, it's more so i² = -1.
Yeah, my bad. :p

It's because i can refer to +sqrt(-1) and -sqrt(-1) isn't it?
 

tommykins

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Continuum said:
Yeah, my bad. :p

It's because i can refer to +sqrt(-1) and -sqrt(-1) isn't it?
-sqrt-1 = -i

I really don't know why, but I've read it numerous times that the definition of i is that i² = -1.
 

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