Simple question-- but im still not getting it right, need quick help (1 Viewer)

[sando]

The burning of sulfur can be desrcibed as:

S + O2 ----) SO2

What volume of sulfur dioxide gas will be released at 25'C and 101.3 kPa when 8.00g of sulfur is burnt ???


Can someone plz include full working out, so i can see where my calculations have gone wrong. Thanks

 

[Riviet]

n=M/m
=8/32.1
Since one mole of sulfur burns to produce 1 mole of sulfur dioxide,
number of moles of SO₂ = 8/32.1

n=V/V_m
V=n.V_m
=(8/32.1)x24.47
=6.1 L

 

[sando]

oh my goodness.... i realised what i did

punched it into calculator wrong

thanks 4 that