sin(theta)/3 = 2/sinx+2 (1 Viewer)

[ProdigyInspired]

Hi,

Sorry again, thank you guys so much for your help.

I've tried doing this and ended up with theta being an undefined answer as it gives me that sin theta is more than one or is negative.

So here's what I did. I'll make theta = x for simplicity sakes.

sin(x) = 6/(sinx + 2)
sin(x) * (sinx) + 2 = 6
sin^2 x + 2 sin x = 6
sin^2 x + 2 sin x - 6 = 0
Using quadratic formula I get:
sin x = -1 +- sqrt(7)
Tried to use sine inverse to find x but gives me undefined, did I do something wrong?

edit: my bad I named the title wrong, just imagine sinx to be theta.


Again, thank you guys so much, you guys are legends.

 

[InteGrand]

Hi,

Sorry again, thank you guys so much for your help.

I've tried doing this and ended up with theta being an undefined answer as it gives me that sin theta is more than one or is negative.

So here's what I did. I'll make theta = x for simplicity sakes.

sin(x) = 6/(sinx + 2)
sin(x) * (sinx) + 2 = 6
sin^2 x + 2 sin x = 6
sin^2 x + 2 sin x - 6 = 0
Using quadratic formula I get:
sin x = -1 +- sqrt(7)
Tried to use sine inverse to find x but gives me undefined, did I do something wrong?

edit: my bad I named the title wrong, just imagine sinx to be theta.


Again, thank you guys so much, you guys are legends.

You seem to have done everything right, which means the equation has no solution.

 

[ProdigyInspired]

You seem to have done everything right, which means the equation has no solution.

Alright thanks, I was worried I did something wrong.