Sketching Snell's Law (1 Viewer)

Aerath

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I think it's sin r that goes on the x axis. That's what my textbook says. :\
 

undalay

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Normally the independent variable is on the x-axis.
So that would be sin i?
 

dpospination

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sin r goes on the x axis, and sin i on the y axis, because u need the gradient, rise over run to give u sneels law, and sin i/sin r is snells law and gradient. if u were graphiing angle i and angle r, then angle i is independat vairable and would go on the x axis, but in this case it is not.

angle of refraction is dependant on angle of incidence, but i dont think sin i is dependant on sin r
 

Aerath

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Not quite sure what you managed to get from us - two of us said sin r, and another two said sin i. If anything, we just reinforced your doubt. :p
 

tanna

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I always did sin r on the x-axis...and that's what our teacher told us
 

x.Exhaust.x

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Aerath said:
Not quite sure what you managed to get from us - two of us said sin r, and another two said sin i. If anything, we just reinforced your doubt. :p
Lol exactly what I was thinking :).
 

the-derivative

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sikhman said:
i think the conclusion to draw is that it doesn't really matter....except if you were conducting an experiment, in which case independent variable always goes on x axis (according to what i've learnt)
Yeah, thats pretty much what i concluded to. Well what I got out of this was basically, that I could do either and prob wouldn't lose marks, which is basically my main concern.
 

x.Exhaust.x

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So what exactly is it? The-derivative how did you graph it in the end? I have a physics half yearly exam tomorrow and I know it'll pop up somewhere :D.
 

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