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sorta related to aux angle/trig (1 Viewer)

menty

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OK
when i do these questions, i usually end up in the form cosAcosB -sinAsnB = R
thats easy, its just cos (A-B) = R
if i have problems, and i wasnt b int he beginning, i just make it cos (B-A) = R (cuz cos (-A) = cos(A)

Now, what happens if i want cosAcosB + sinAsnB instead?
DOES (sinAsinB - cosAcosB) = - (cosAcosB -sinAsinB)
 

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