struggling in trig! (1 Viewer)

[xoxo]

im finding the 3u part of trig challenging and came across this q that i can recognise but cant seem to find the way to get the answer out
can anyone help plz?

sin 2x__
1+ cos2x

thanx

 

[SoulSearcher]

What are we supposed to do in this question?

 

[hyparzero]

sin(2x) = 2sin(x)cos(x) ...... (1)
and

1 + cos(2x) =2cos²(x) ......(2) (why?)

=======================================
Reason:
----------
1 + cos(2x) = 1 + cos²(x) - sin²(x)
=> 1 + cos(2x) = cos²(x) + sin²(x) + cos²(x) - sin²(x)

.'. 1 + cos(2x) =2cos²(x)

========================================

(1) / (2) = sin(2x)/(1+ cos(2x))
= [2sin(x)cos(x)] / [2cos²(x)]

= tan(x)

Q.E.D

 

[xoxo]

wow
u make it look so easy
lol
thanx SOO much

 

[Sober]

The only flaw in the asnwer was the QED, since it translates to "which was to be demonstrated". As far as I can see the question didn't ask for anything to be demonstrated

 

[hyparzero]

in my vocab, QED stands for: Quantified Elephant Doodles