A abdog Member Joined Jul 21, 2012 Messages 155 Gender Undisclosed HSC N/A Mar 15, 2013 #1 10^2x - 5(10^x) + 4 = 0 I substituted x for u, and got u=1 and 4. My question is, 10^x=1, so x=0. But 10^x=4, what is x for this?
10^2x - 5(10^x) + 4 = 0 I substituted x for u, and got u=1 and 4. My question is, 10^x=1, so x=0. But 10^x=4, what is x for this?
D94 New Member Joined Oct 5, 2011 Messages 4,419 Gender Male HSC N/A Mar 15, 2013 #2 You can use logarithms to determine x. 10x = 4 So, log(10x) = log(4) x log(10) = log(4) Therefore, x = log(4) / log(10)
You can use logarithms to determine x. 10x = 4 So, log(10x) = log(4) x log(10) = log(4) Therefore, x = log(4) / log(10)
