the shipwrecks q *again.. ^^ (1 Viewer)

[Frigid]

Originally posted by ND
both the water and the Cu (2+) will be reduced.

errr... ND, there are no Cu2+ ions to be reduced. our original scenario was iron strip, copper strip, water in beaker.

 

[ND]

Originally posted by Frigid

errr... ND, there are no Cu2+ ions to be reduced. our original scenario was iron strip, copper strip, water in beaker.

I mean the Cu(2+) ions from the oxidation of the copper strip.

 

[+:: $i[Q]u3 ::+]

thanks shannon~~!!!!!!!!! =D *much happier*

ND... the metals are in a beaker. the copper wouldn't corrode.

 

[mercury]

YUM CHA!!!

then i think of...
esters!
food preservatives!
benzoic acid!

no no *shakes head* bad association

 

[+:: $i[Q]u3 ::+]

Originally posted by mercury
YUM CHA!!!

whooooo hooooooo =D
*3days to go*

 

[ND]

Originally posted by +:: $i[Q]u3 ::+
thanks shannon~~!!!!!!!!! =D *much happier*

ND... the metals are in a beaker. the copper wouldn't corrode.

If the beaker is just water, and they are far apart, they would both corrode separately (as water isn't a good conductor). But if they are touching, the copper would still corrode but it is quickly reduced by the electrons from the oxidation of the iron, which is why it doesn't really corrode (if you understand what i mean). Some of teh electrons go into reducing the copper back, some go into reducing the water.