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trials: Maths revision Q (1 Viewer)

-pari-

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have some maths Q from my revision. they're not past paper Q...


1) the cost of running a car at an average speed of v km/h is given by c = 15 + (v^2)/80 cents per hour
find the average speed to the nearest km/h at which the cost of a 500 km trip is a minimum.

answer from memory: 110

2) amy and kevin worked out that they would save $50 000 in 5 years by depositing all of their combined monthly salary of $S at the beginning of each month into a savings account and withdrawing $1600 at the end of each month for living expenses. the savings account paid interest at the rate of 3% p/a compounded monthly.

-a)show that at the end of the 2nd month the balance in their savings account, immediately after making their withdrawal of $1600, would be given by
S[(1.0025^2 - 1.0025) S - 1600 (1.0025 + 1) ]

-b) hence write down an expression for the balance in their account at the end of the sixtieth month

c) calculate their combined monthly savings.
answer: $2367.52

3) a man wishes to have %20 000 in 15years time. he proposes to make a finance company 15 equal payments commencing now (the last payment being made 1 year before $20 000 is to be paid to him). Assuming interest is paid by the company at 12% p.a. find what should be the amount of each payment.

4) Two men, Dave and Carl work on an annual salary of $10 000. Dave recieves an increment of $1000 p.a. whilst Carl recieves an increment of $500 every 6months. Who has recieved the greater amount after 10 years and by how much?
answer: Carl, by $2500

5) Ben starts with a salary of $390/wk and recieves a half yearly increase of $30 /wk.
1 year = 52 weeks; find the total amound received during the first n years.
answer: 780n(25+2n)
 

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3) Sn = a (rn - 1) / r - 1

Sn = $20,000 (man wants %20,000, actually $20,000)
r = 1.12 (Amount the man is getting paid)
a = ? (How much should man be paid every year ?)

a (1.1215 - 1) / 1.12 - 1 = 20000
a (1.1215 - 1) = 20000 (1.12 - 1)
a = 20000 (1.12 - 1) / (1.1215 - 1)
a = 536.4847929...
a = $536.50 (to the nearest 5 cents)

.: Man should be paid $536.50 to the nearest 5 cents
 

Mattamz

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-pari- said:
have some maths Q from my revision. they're not past paper Q...


1) the cost of running a car at an average speed of v km/h is given by c = 15 + (v^2)/80 cents per hour
find the average speed to the nearest km/h at which the cost of a 500 km trip is a minimum.

answer from memory: 110
i think you made a mistake the equation should be c = 150 + (v^2)/80; heres how its done.

v=x/t, therefore v = 500/t

c = 150 + (v^2)/80 (cost in cents/hour),
C= 150t + (v^2)t/80 (total cost in cents)
=150t + 250 000/80t since v=500/t
=150t + 3125/t

dC/dt = 150 - 3125/(t^2)
stat pt when dC/dt = 0;
150(t^2) = 3125
(t^2) = 3125/150
t= 4.56435465... ( since t>0)

sub t= 4.56435465 into v =500/t
v = 500/4.56435465
= 109.544512...
= 110 (nearest decimal)

therefore speed for the cost to be a minimum is 110km/h
 

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