tricky probe-ability! (1 Viewer)

[roosterman]

Please help

1a) in how many ways can 3 horses win 1st, 2nd, and 3rd places in a race (trifecta) if there are 8 horses?

b)if i choose different selections of 3 horses, find the probability that i chose the horse that win the first 3 places.

 

[insert-username]

1a) in how many ways can 3 horses win 1st, 2nd, and 3rd places in a race (trifecta) if there are 8 horses?

I think this is a permutation - 8P3, or 8!/(8-3)! - 336 ways.


I_F

 

[roosterman]

Does anyone have other suggestions ?????

 

[i4ct]

1a) in how many ways can 3 horses win 1st, 2nd, and 3rd places in a race (trifecta) if there are 8 horses?

This is actualy a combination question, because the combination probability of 3 horses winning 1,2,3 in any order.
therefore answer: 8C3 = 56 ways

 

[ephemeral]

I'm pretty sure it's 336. A trifecta at the races with 8 horses in it costs $336.

 

[insert-username]

Order matters in this question - a result of ABC is not the same as BCA, since different horse have come 1st, 2nd, and 3rd. If order didn't matter, then it would be a combination.


I_F

 

[Sober]

1a) in how many ways can 3 horses win 1st, 2nd, and 3rd places in a race (trifecta) if there are 8 horses?

This is actualy a combination question, because the combination probability of 3 horses winning 1,2,3 in any order.
therefore answer: 8C3 = 56 ways

That's a boxed trifecta

 

[.ben]

roosterman goes to tipps?