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Trig help (1 Viewer)
- Thread starter karoooh
- Start date
P
pLuvia
Guest
Solving it?
cosx=1-cosx
2cosx=1
cosx=1/2
x=pi/3, 5pi/3
cosx=1-cosx
2cosx=1
cosx=1/2
x=pi/3, 5pi/3
Hi Carolyn! Haven't talked to you in ages. 
cosx = 1- cosx
2cosx = 1
cosx = 1/2
x = pi/3, 5pi/3, 7pi/3...
or a general solution:
x=2.pi.n + pi/3, n is an integer
If you want to do it by graphing, graph y=cosx and y=1-cosx on the same set of axes and all intersection points of the two curves will be your solutions.
Hope that helps.
cosx = 1- cosx
2cosx = 1
cosx = 1/2
x = pi/3, 5pi/3, 7pi/3...
or a general solution:
x=2.pi.n + pi/3, n is an integer
If you want to do it by graphing, graph y=cosx and y=1-cosx on the same set of axes and all intersection points of the two curves will be your solutions.
Hope that helps.
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