Q19
If A, B, C are supposed to be 3 consecutive vertices, in cyclic order, (adjacent sides BA and BC), then there is only one D. In cyclic order, B-A-C (adjacent sides AB & AC) will generate another D and finally A-C-B (adjacent sides CA & CB) a 3rd D. A-B-C and C-B-A are treated as the same, etc etc.
Will provide solution after my lunch and afternoon news.
Q12 is a similar problem to Q19.