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Velocity!!! (1 Viewer)

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hey people,

just wondered one equation from science.

It states that if a body has an initial velocity of u m/s and it accelerates at a rate of a m/s^2 for a time period of tseconds, its velocity v is given by the formula:

v = u + at

can anyone tell me how to understand this equation in simple language?
 

BackCountrySnow

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final velocity equals initial velocity plus acceleration times time taken. :giddy:
 
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Because acceleration is measured in m/s/s, if you multiply it by time taken you will find out the extra velocity gained in the time it accelerated. This combined with the initial velocity it was travelling allows you to calculate the final velocity of the object after t seconds.
 

kaz1

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Since aceleration is change in speed over time or a = (v - u)/t
You multiply both sides by t and you get, at = v - u
Then you add both sides by u and you get v = u + at
 

BackCountrySnow

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acceleration is the change in velocity over time..
it doesn't have to be an increase.
 

Aplus

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When an object experiences a uniform acceleration, its velocity increases linearly. The average acceleration is given by:
a = v - u / t
Rearranging the equation, we get the formula:
v = u + at
Where velocity is the rate of change of position, acceleration is the rate at which the velocity is increasing and initial velocity is the velocity of the object, prior to its change. Time obviously represents how long the object experiences this acceleration.
 

Aplus

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Forbidden. said:
d = ut + ½at2
v = u + at
a = a

Differentiate each one with respect to t lol.
But graph v vs. t in the 2nd equation, like y = mx + b from Year 9 maths was it?
Yes, the velocity increases linearly.
 

Forbidden.

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Aplus said:
Yes, the velocity increases linearly.
Yeah, if we were to graph v = u + at,
if a particle had an initial velocity u, then it would appear as a constant on the graph.
The acceleration determines the slope of the graph and t, time is how long the particle travelled and it represents an interval or bound on the graph.
 

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