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VERY URGENT and easy question --> HELP (1 Viewer)
- Thread starter Mr_Kap
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keepLooking
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- Aug 25, 2014
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- 2015
Expand 2a(x+1)^2 +b(x+1) + c
Rearrange.
^2+b(x+1)+c\\2ax^2+4ax+2a+bx+b+c\\(2a)x^2+(4a+b)x+(2a+b+c)\\\\2x^2-5x+7 \\\\ $You know that $ 2a = 2 \\ \therefore a = 1\\$You know that $ -5 = 4a + b $ \\ -5 = 4 + b \\ \therefore b = -9 \\ 7 = 2a + b + c \\ 7 = 2 - 9 + c \\ c = 14 )
Rearrange.
Last edited:
thank god..Expand 2a(x+1)^2 +b(x+1) + c
Rearrange.
^2+b(x+1)+c\\2ax^2+4ax+2a+bx+b+c\\(2a)x^2+(4a+b)x+(2a+b+c)\\\\$You know that $ 2a = 2 $ \\ \therefore a = 1\\$You know that $ -5 = 4a + b $ \\ -5 = 4 + b \\ \therefore b = -9 )
i did that but wasnt sure if it was correct. thx!
And c = 14.