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Volume question (1 Viewer)

Xayma

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V=&pi;<sup>ln 2</sup>&int;<sub>0</sub> [u(x)<sup>2</sup>-v(x)<sup>2</sup>]
V=&pi;<sup>ln 2</sup>&int;<sub>0</sub> [R<sup>2</sup>+2R(e<sup>x</sup>-1)+(e<sup>x</sup>-1)<sup>2</sup>-R<sup>2</sup>-2R(1-e<sup>x</sup>)-(1-e<sup>x</sup>)<sup>2</sup>]
V=&pi;<sup>ln 2</sup>&int;<sub>0</sub> [2R(e<sup>x</sup>-1)-2R(1-e<sup>x</sup>)]
V=&pi;<sup>ln 2</sup>&int;<sub>0</sub> [2R(e<sup>x</sup>-1)+2R(e<sup>x</sup>-1)]
V=4R&pi;<sup>ln 2</sup>&int;<sub>0</sub>[e<sup>x</sup>-1]
V=4R&pi;[e<sup>x</sup>-x]<sup>ln 2</sup><sub>0</sub>
V=4R&pi;[2-ln 2-1+0]
V=4R&pi;[1-ln 2]
But 2[1-ln 2]=A
&there4;
V=2&pi;RA
 

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