bennyngo12345678
New Member
- Joined
- Jan 17, 2015
- Messages
- 4
- Gender
- Male
- HSC
- 2015
The question is within the image. Thanks so much for the help, kinda stuck on the fact that there are three curves and not sure how to approach it in this sense
-
Want to help us with this year's BoS Trials? Let us know before 30 June. See this thread for details -
Looking for HSC notes and resources? Check out our Notes & Resources page
Volumes slicing method help (1 Viewer)
- Thread starter bennyngo12345678
- Start date
integral95
Well-Known Member
- Joined
- Dec 16, 2012
- Messages
- 779
- Gender
- Male
- HSC
- 2013
I suppose you should use the cylindrical shell method (my 4U maths is quite rusty btw)
 = \\ \\ \frac{x}{2}-\sqrt{x^2-12} \\ \\ $The radius is x since you're rotating from the y-axis and the volume is$ \\ \\ \\ 2\pi\int_{a}^{b}(radius)(height) \ \ dx = \\ \\ 2\pi\int_{3}^{4}x(\frac{x}{2}-\sqrt{x^2-12}) \ \ dx )
FrankXie
Active Member
did you guys notice that the diagram was wrong? if you based your solution on the sketch given, you would get incorrect answer.
integral95
Well-Known Member
- Joined
- Dec 16, 2012
- Messages
- 779
- Gender
- Male
- HSC
- 2013
ahhhh crap you're right the hyperbola isn't even defined at x=3