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Find the volume generated when the region bounded by the given curve and lines is rotated about the x-axis

y=x^2+2 and y=x+4

yea havin troubles with volumes.
 

Trebla

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This is just a typical volume between two curves:
V = π(from -1 to 2)∫(x + 4)² dx - π(from -1 to 2)∫(x² + 2)² dx
= π(from -1 to 2)∫(x² + 8x + 16 - [x4 + 4x² + 4]) dx
= π(from -1 to 2)∫(x² + 8x + 16 - x4 - 4x² - 4]) dx
= π(from -1 to 2)∫(- 3x² + 8x + 12 - x4) dx
= π [- x³ + 4x² + 12x - x5/5] (from -1 to 2)
= π (128/5 - (- 34/5))
= 162π/5 cubic units

check my working...
 

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