YEAR 12 ADVANCED TRIGONOMETRIC EQUATIONS (1 Viewer)

ebony_17

New Member
Joined
Jun 4, 2020
Messages
11
Gender
Female
HSC
2021
Graph y = -cos(x) + 3 and y = x-1 for [0 2pi]
then solve
-cos(x) + 3 = x-1
and -cos(x) + 3 = 2
The solving algebraically is where I'm getting confused.maths.PNG
 

cossine

Well-Known Member
Joined
Jul 24, 2020
Messages
583
Gender
Male
HSC
2017
Graph y = -cos(x) + 3 and y = x-1 for [0 2pi]
then solve
-cos(x) + 3 = x-1
and -cos(x) + 3 = 2
The solving algebraically is where I'm getting confused.View attachment 29536
-cos(x) +3 = x - 1

=> -cos(x) - x + 4 = 0

I don't think is there an algebraic way. to solve this.

I would try Newton's method but that will only give you an approximate solution.
 

black.mamba

Active Member
Joined
May 15, 2020
Messages
213
Location
Vern Gang
Gender
Male
HSC
2020
im guessing the question is just asking for answers to a few decimal places, which can be found on desmos as the x-coordinates of the intersection points
 

CM_Tutor

Moderator
Moderator
Joined
Mar 11, 2004
Messages
2,644
Gender
Male
HSC
N/A
Graph y = -cos(x) + 3 and y = x-1 for [0 2pi]
then solve
-cos(x) + 3 = x-1
and -cos(x) + 3 = 2
The solving algebraically is where I'm getting confused.
The second equation here,



is solvable, though
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top