C cutemouse Account Closed Joined Apr 23, 2007 Messages 2,250 Gender Undisclosed HSC N/A Oct 21, 2008 #1 Hi, Here's the question, I have no idea on how to do it. If 1, ω, ω2 are the 3 cube roots of unity, prove that (a+bω+cω2)/(b+cω+aω2)= ω Thanks, Jason
Hi, Here's the question, I have no idea on how to do it. If 1, ω, ω2 are the 3 cube roots of unity, prove that (a+bω+cω2)/(b+cω+aω2)= ω Thanks, Jason
namburger Noob Member Joined Apr 29, 2007 Messages 228 Gender Male HSC 2008 Oct 21, 2008 #2 LHS: (a+bω+cω^2)/(b+cω+aω^2) = (aω^3+bω+cω^2)/(b+cω+aω^2) as ω^3 = 1 = ω(aω^2+b+cω)/(b+cω+aω^2) = ω
K kooltrainer New Member Joined Jun 17, 2006 Messages 659 Gender Male HSC 2008 Oct 21, 2008 #3 too goood
C cutemouse Account Closed Joined Apr 23, 2007 Messages 2,250 Gender Undisclosed HSC N/A Oct 21, 2008 #4 Geez that was simple ... Thank you!!