M maths94 Member Joined Jul 14, 2009 Messages 448 Gender Male HSC 1998 Aug 16, 2009 #1 just some hw that im stuck on...we have to express the answer in general form btw y-2=1/2x-3<--how could i express that in general form? i can do this y+8=4x-12 4x-y-20=0 so ye need help lol
just some hw that im stuck on...we have to express the answer in general form btw y-2=1/2x-3<--how could i express that in general form? i can do this y+8=4x-12 4x-y-20=0 so ye need help lol
Dragonmaster262 Unorthodox top student Joined Jan 1, 2009 Messages 1,386 Location Planet Earth Gender Male HSC 2010 Aug 16, 2009 #2 Multiply both sides by 2x-3 like this: (y-2)(2x-3)=1(2x-3) Simplify this and move everything to the right hand side.
Multiply both sides by 2x-3 like this: (y-2)(2x-3)=1(2x-3) Simplify this and move everything to the right hand side.
M maths94 Member Joined Jul 14, 2009 Messages 448 Gender Male HSC 1998 Aug 16, 2009 #3 Dragonmaster262 said: Multiply both sides by 2x-3 like this: (y-2)(2x-3)=1(2x-3) Simplify this and move everything to the right hand side. Click to expand... btw my original equation was y-2=1/2x-3...y would i times both sides by 2x-3...btw in my equation the x is a half.
Dragonmaster262 said: Multiply both sides by 2x-3 like this: (y-2)(2x-3)=1(2x-3) Simplify this and move everything to the right hand side. Click to expand... btw my original equation was y-2=1/2x-3...y would i times both sides by 2x-3...btw in my equation the x is a half.
Dragonmaster262 Unorthodox top student Joined Jan 1, 2009 Messages 1,386 Location Planet Earth Gender Male HSC 2010 Aug 16, 2009 #4 maths94 said: btw my original equation was y-2=1/2x-3...y would i times both sides by 2x-3...btw in my equation the x is a half. Click to expand...
maths94 said: btw my original equation was y-2=1/2x-3...y would i times both sides by 2x-3...btw in my equation the x is a half. Click to expand...