Trig question (1 Viewer)

[deltaxray]

Hi. Can someone please help me with the following trig question

If a/sin(x) = b/cos(x) show that sin(x)cos(x) = ab/a^2+b^2

Thanks. Much appreciated

 

[untouchablecuz]

Hi. Can someone please help me with the following trig question

If a/sin(x) = b/cos(x) show that sin(x)cos(x) = ab/a^2+b^2

Thanks. Much appreciated

a/sin(x) = b/cos(x)

sinx/cosx=a/b

i.e. tanx=a/b

draw the triangle with opposite side = a, adjacent side=b and hypoteuse=a^2+b^2

sinx=a/sqrt(a^2+b^2)

cosx=b/sqrt(a^2+b^2)

sinxcosx=ab/(a^2+b^2)

 

[Prashant Sallan]

hopefully this is right...

 

[Prashant Sallan]

a/sin(x) = b/cos(x)

sinx/cosx=a/b

i.e. tanx=a/b

draw the triangle with opposite side = a, adjacent side=b and hypoteuse=a^2+b^2

sinx=a/sqrt(a^2+b^2)

cosx=b/sqrt(a^2+b^2)

sinxcosx=ab/(a^2+b^2)

beat me to it.. i knew there was a faster way.. gud goin!