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confuesd..help??????? (1 Viewer)

we0426

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can some on plzz help me in this question...i dont have the answer for this question and i want to know if i am doing it right???

and i know u all know what it means but just to make sure x^2 means (x squrd)


the gradient of a curve is given by....

2x
dy/dx= --------
x^2 +e

THe curve pasess through the pts(0,2)

what is the equation of the curve??:cry:
 
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annabackwards

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If you integrate (dy/dx) you get y = int (dy/dx) = int (2x / x^2 +e) = Ln (x^2 +e) + c

Therefore y = Ln (x^2 +e) + c

Sub in (0, 2)
2 = Ln (0^2 + e) + c
So c = 2 - Ln e = 2 - 1 = 1

Therefore equation of curve is y = Ln (x^2 +e) + 1
 
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we0426

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If you integrate (dy/dx) you get y = int (dy/dx) = int (2x / x^2 +e) = Ln (x^2 +e) + c

Therefore y = Ln (x^2 +e) + c

Sub in (0, 2)
2 = Ln (0^2 + e) + c
So c = 2 - Ln e = 2 - 1 = 1

Therefore equation of curve is y = Ln (x^2 +e) + 1
OMG I AM RIGHT...THANK U SOO MUCH...


LOVE U..TO BITSSS..:uhhuh::hammer::hammer::hammer::hammer::hammer::hammer:
 

Drongoski

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I cannot understand yr question> But assuming it is:


 

annabackwards

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YESS PERCSISLY....OH..WAIT LOL..HOW DO U WRITE UR MATHS QUESTION LIKE THAT.....I WANT TO LEARN 2:uhhuh:
There's a button at the bottom where you reply called "Launch LaTex Equation Editor". Just click the quick reply button before you click that and you can write equations like Drogonski did :)
 

we0426

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There's a button at the bottom where you reply called "Launch LaTex Equation Editor". Just click the quick reply button before you click that and you can write equations like Drogonski did :)

hahaah..thanks thats soo..i mean soo..SOO coollllllll:hammer:
 

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